书签 主页 联系
  • 示例
  • 示例数据库
#1
SELECT COUNT(*) FROM employees;
#2
SELECT COUNT(*) FROM employees WHERE department_id = 6;
#3
SELECT COUNT(*) FROM employees WHERE job_id = 9;
#4
SELECT department_id, COUNT(*) FROM employees GROUP BY department_id;
#5
SELECT e.department_id, department_name, COUNT(*) FROM employees e INNER JOIN departments d ON d.department_id = e.department_id GROUP BY e.department_id;
#6
SELECT e.department_id, department_name, COUNT(*) FROM employees e INNER JOIN departments d ON d.department_id = e.department_id GROUP BY e.department_id ORDER BY COUNT(*) DESC;
#7
SELECT e.department_id, department_name, COUNT(*) FROM employees e INNER JOIN departments d ON d.department_id = e.department_id GROUP BY e.department_id HAVING COUNT(*) > 5 ORDER BY COUNT(*) DESC;
#8
SELECT COUNT(job_id) FROM employees;
#9
SELECT COUNT(DISTINCT manager_id) FROM employees;
表格列表
国家
SELECT * FROM countries;
部门
SELECT * FROM departments;
受抚养人
SELECT * FROM dependents;
员工
SELECT * FROM employees;
工作
SELECT * FROM jobs;
地方
SELECT * FROM locations;
地区
SELECT * FROM regions;
  • SQL 查询
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  • 结果