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  • 示例
  • 数据库样本
#1
SELECT manager_id, first_name, last_name, COUNT(employee_id) direct_reports FROM employees WHERE manager_id IS NOT NULL GROUP BY manager_id;
#2
SELECT manager_id, first_name, last_name, COUNT(employee_id) direct_reports FROM employees WHERE manager_id IS NOT NULL GROUP BY manager_id HAVING direct_reports >= 5;
#3
SELECT department_id, SUM(salary) FROM employees GROUP BY department_id HAVING SUM(salary) BETWEEN 20000 AND 30000 ORDER BY SUM(salary);
#4
SELECT e.department_id, department_name, MIN(salary) FROM employees e INNER JOIN departments d ON d.department_id = e.department_id GROUP BY e.department_id HAVING MIN(salary) >= 10000 ORDER BY MIN(salary);
#5
SELECT e.department_id, department_name, ROUND(AVG(salary), 2) FROM employees e INNER JOIN departments d ON d.department_id = e.department_id GROUP BY e.department_id HAVING AVG(salary) BETWEEN 5000 AND 7000 ORDER BY AVG(salary);
表清单
countries
SELECT * FROM countries;
departments
SELECT * FROM departments;
dependents
SELECT * FROM dependents;
employees
SELECT * FROM employees;
jobs
SELECT * FROM jobs;
locations
SELECT * FROM locations;
regions
SELECT * FROM regions;
  • SQL 查询
执行
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  • 结果